Talk:LibVLC Tutorial 0.9
This code doesn't appear to compile. I am using gcc 3.4. But some of the problems are obvious, eg line 6, the parentheses don't match.
What version of libvlc was used to create the tutorial? Functions libvlc_media_... don't appear to exist in the latest release version, 0.8.6c. If an unreleased version is used for the tutorial, that would be fine, if the text mentioned that.
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The code wasn't tested, but should work using 0.9.0, or at least show how to use.--Pdherbemont 22:36, 19 August 2007 (CEST)
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I am new to this wiki, and I don't want to jump too far ahead. However, I have modified the tutorial code so that it compiles and runs on cygwin gcc 3.4 and windows XP, using the latest released vlc version 0.8.6c.
I will paste the code here, in the talk page, in case it would be a violation of etiquette to just dump the code on the main page. Note the code on the main page has syntax errors at least, and either it has big prototyping problems or else the related API's are substantially different in whatever vlc version the author used to compile against.
Note for linux, remove <windows.h>, change "Sleep (10000)" to "sleep (10)".
- include <stdio.h>
- include <windows.h>
- include <vlc/libvlc.h>
static void quit_on_exception (libvlc_exception_t *excp) {
if (libvlc_exception_raised (excp)) { fprintf(stderr, "error: %s\n", libvlc_exception_get_message(excp)); exit(-1); }
}
int main(int argc, char **argv) {
libvlc_exception_t excp; libvlc_instance_t *inst; int item; char *myarg0 = "-I"; char *myarg1 = "dummy"; char *myarg2 = "--plugin-path=c:\\program files\\videolan\\plugins"; char *myargs[4] = {myarg0, myarg1, myarg2, NULL}; char *filename = "c:\\video\\main\\Everybody_Hates_Chris_Feb_26.mpg";
libvlc_exception_init (&excp); inst = libvlc_new (3, myargs, &excp); quit_on_exception (&excp); item = libvlc_playlist_add (inst, filename, NULL, &excp); quit_on_exception (&excp); libvlc_playlist_play (inst, item, 0, NULL, &excp); quit_on_exception (&excp); Sleep (10000); libvlc_destroy (inst); return 0;
}